In any ferric salt, on adding potassium ferrocyanide, a prussian blue colour is obtained, which is
Or
Ferric ions form Prussian blue coloured precipitate due to

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$K_{3} Fe {(CN)}_{6}$

${Fe}_{4} {[Fe (CN)_{6}]}_{3}$

$KFe [Fe {(CN)}_{6}]$

${FeSO}_{4} \cdot Fe (CN)_{6}$

answer is D.

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Detailed Solution

$\begin{array}{cc} 3 K_{4} [Fe (CN)_{6}] + 4 {FeCl}_{3} & \to {Fe}_{4} {[Fe (CN)_{6}]}_{3} + 12 KCl \\ Pot. ferrocyanide & Ferri ferrocynide \\ (Prussian blue) \end{array}$

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