In astronomical telescope, In the normal adjustment position, the magnification obtained by the telescope is given by

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m = fe / (fo+fe)

m = f0 / (fo+fe)

m = fe/fo

m = fo/ fe

answer is B.

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Detailed Solution

In an astronomical telescope, In the normal adjustment position, the length of the telescope (L) (which is the distance between objective and eye piece) is equal to the sum of the focal lengths of the objective and the eye piece (L = fo + fe). In the normal adjustment position, the magnification obtained by the telescope is given by m = fo / fe

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