In B₂H₆, two H atoms complete octets of two B-atoms oscillation between them taking the electrons of the bonds formed. These bonds are called

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banana bonds

3C – 2e bonds

hydrogen bridge bonds

all of these

answer is D.

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Detailed Solution

Diborane is an electron deficient compound. In diborane, total number of valence electrons is 12.
Diborane contains two coplanar ${BH}_{2}$ groups.
Diborane has four terminal hydrogen atoms and the two boron atoms lie in one plane.
Above and below this plane, there are two bridge hydrogen atoms.
The bridge hydrogen atoms are present in a plane perpendicular to rest of the molecule.
Each bridge hydrogen is bonded to the two boron atoms only by sharing of two electrons.
These are called three centered two electron $(3 c - 2 e^{-})$ bonds, also known as banana or tau bonds.
The terminal B−H bonds are $2 c - 2 e^{-}$ bonds.