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Q.

In Bohr’s theory the potential energy of an electron at a position is  Kr22 (where  K is a positive constant); then the quantized energy of the electron in nth orbit is: 

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a

nh2πKm

b

nh2πKm12

c

nhKm

d

nh2πmK12

answer is B.

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Detailed Solution

Given
Potential energy of an electron  U=Kr22
Where  K=Positive constant
We use force on electron 
F=dUdr=Kr=mv2rFc=mv2rmv2=Kr2  and mvr=nh2πmrKmr=nh2π r=nh2πKm

Energy of nth orbit is 

En=Kr22+Kr22=Kr2En=Knh2πKm=nh2πKm

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