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In Boyles experiment for a given gas at different temperatures the graph drawn between pressure and density are straight lines as shown then

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$T_{1} = T_{2}$

$T_{2} > T_{1}$

$T_{1}^{3} = T_{2}$

$T_{1} > T_{2}$

answer is A.

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Detailed Solution

$P = constant , At constant pressure d \propto \frac{1}{T} from graph d_{2} > d_{1} then T_{2} < T_{1}$

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