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In Boyle's experiment for a given gas at different temperatures, the graph drawn between pressure and density are straight lines as shown, then

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T₁ > T₂

T₂ > T₁

T₁ = T₂

T₁³ = T₂

answer is A.

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Detailed Solution

We know, PV = nRT

Rightarrow PV = left( {nM} right)frac{{RT}}{M} = mfrac{{RT}}{M}

where M = molar mass and m = Mass of gas.

therefore P = left( {frac{m}{V}} right)frac{{RT}}{M} = dleft( {frac{{RT}}{M}} right)

where RT/M = Slope of P-d graph.

therefore frac{{R{T_2}}}{M} < frac{{R{T_1}}}{M}

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