In bromination of propyne, with bromine 1, 1, 2, 2-terabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2 tetrabromopropane obtained from 1 g of bromine in this reaction is ________________ x $10^{- 1} g .$ (Nearest integer)
(Molar mass : Bromine = 80 g/mol

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answer is 3.

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Detailed Solution

$= \frac{1}{160} \times \frac{1}{2} \times 360 \times 0.27$

$= 0.30375$

$= 3.0375 \times 10^{- 1}$

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