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In carius method 0.3905 g of an organic compound gave 0.7175 g of silver chloride calculate the percentage of Chlorine in the compound

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48.45

54.56

45.45

answer is C.

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Detailed Solution

$% o f c h l o r i n e = \frac{W e i g h t o f A g C l \times 35.5 \times 100}{W e i g h t o f substance \times 143.5}$

$= \frac{0.7175 \times 35.5 \times 100}{0.3905 \times 143.5}$

$= \frac{5}{1000} \times \frac{1000}{11} \times 100$

$= 45.45$

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