In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is _______ %.
[Given : molar mass in g mol^{– 1} of Ag : 108, Cl = 35.5]

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Detailed Solution

$\begin{array}{l} n_{Cl} = n_{AgCl} = \frac{143.5 \times 10^{- 3}}{143.5} = 10^{- 3} \\ % Cl = \frac{10^{- 3} \times 35.5}{180 \times 10^{- 3}} \times 100 = 19.72 \end{array}$

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