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Q.

In Carius method of estimation of halogen, 0.172g of an organic compound showed presence of 0.08g of bromine which of these is the correct structure of the compound .

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a

$H_{3} C - {CH}_{2} - Br$

b

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c

$H_{3} C - Br$

d

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answer is B.

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Detailed Solution

Mole of bromine $\frac{0.08}{80} = 10^{- 3} mole$
$\Rightarrow \frac{0.172}{m} = 10^{- 3}$
Molar mass $M = \frac{0.172}{10^{- 3}} = 172 g$

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