In Carius method of estimation of halogen, 0.25 g of an organic compound gave 0.15 g of silver bromide (AgBr). The percentage of Bromine in the organic compound is ____________ × 10^–1% (Nearest integer).
(Given : Molar mass of Ag is 108 and Br is 80 g mol^–1)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 255.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$% Bromine = \frac{Molar Mass of Bro mine}{Molar Mass of Silver bromide} \times \frac{Weight of AgBr}{Weight of sample} \times 100$
$= \frac{80}{188} \times \frac{0.165}{0.25} \times 100 = \frac{4800}{188} = 25.53 = 255 \times 10^{- 1}$

Watch 3-min video & get full concept clarity

hear from our champions

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!