In Carius method of estimation of halogen. 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound.
(Molar masses : AgBr = 188 g mol^-1: Br = 80 g mol^-1)

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34.04%

40.04%

36.03%

38.04%

answer is A.

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Detailed Solution

Mass of organic compound = 0.45 gm

Mass of AgBr obtained = 0.36 gm

$∴$ Moles of AgBr $= \frac{0 .36}{188}$

$∴$ Mass of Bromine $= \frac{0 .36}{188} \times 80 = 0 .1532 gm$

$∴$ % Br in compound $= \frac{0 .1532}{0 .45} \times 100 = 34 .04 %$

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