In case of a real and inverted image, the magnification created by mirror is

This indicates that it is in a bad position. In terms of inversion, a picture is considered virtual when it is produced with the actual object's orientation reversed. The image's height is seen negatively.

We know,

Magnification $\left(\mathrm{M}\right)=\frac{\text{ height of image }\left({\mathrm{h}}_{\mathrm{i}}\right)}{\left.\text{ height of object( }{\mathrm{h}}_0\right)}$

Given that the picture is inverted in this case, the height of the image (h_i) will be negative while the height of the object will be positive.
As a result, a mirror has a negative magnification.

Hence, the correct answer is option B.