In case of peroxides and superoxides, oxidation number of oxygen respectively are

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+1 and -1

$- 1 and - \frac{1}{2}$

$+ \frac{1}{2}$ and $- \frac{1}{2}$

$- \frac{1}{2} and - 1$

answer is B.

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Detailed Solution

In peroxides (such as $H_{2} O_{2}, {Na}_{2} O_{2}$ ), each oxygen atom is assigned an oxidation number of -1 and in superoxides (such as ${KO}_{2}, {RbO}_{2}$ ), it is $- \frac{1}{2}$

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