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Q.

In case of superposition of waves (at x=0). y1=4sin1026πt and y2=2sin1014πt 

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a

The frequency of resulting wave is 510 Hz

b

The amplitude of resulting wave varies with frequency 3 Hz

c

The frequency of beats is 6 Hz

d

The ratio of maximum to minimum intensity is 9

answer is A, B, C, D.

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Detailed Solution

y=y1+y2=2  sin1026πt+4cos6πt  sin1020πtFrequency of resulting  wave=ω2π=1020π2π=510HzAmplitude of resulting  wave   varies    at      frequency=ω2π=6π2π=3Hzfbeat=12π2π=6Hz

lmaxlmin=a1+a22a1a22=(4+2)2(42)2=364=91

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