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Q.

In case of three plane mirrors meeting at a point to form a corner of a cube, if incident light suffers one reflection on each mirror;

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a

the emergent ray is antiparallel to incident one

b

the emergent ray is in opposite phase with the incident one

c

the emergent ray is in phase with the incident one

d

the emergent ray is perpendicular to incident one

answer is A, D.

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Detailed Solution

Question Image

Explanation of Ans (1)

Let incident ray =ai^+bj^+ck^

Reflection take place on x-y plane then reflected ray will be 

ai^+bj^-ck^ after reflection only z component will get reverse.

     Reflected ray = ai^+bj^-ck^

          Now on second reflection y-z plane incident ray is ai^+bj^-ck^ this reflected ray is -ai^+bj^-ck^.

          Third reflection will give reflected ray=-ai^-bj^-ck^

      Angle between final reflected ray & incident ray is 180°.

          Explanation of Ans(4)

          Due to reflection on plane phase of light change by π.

      Emergent ray will be out of phase with incident ray.

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