In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to 3 volt. The voltage across the resistance R₄ is

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1.5 V

1.2 V

0.6 V

0.4 V

answer is A.

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Detailed Solution

$∴ Total current through battery, i = \frac{3}{75}$

$i_{1} = i_{2} = \frac{3}{75 \times 2} = \frac{3}{150}$

current through $R_{4} = \frac{3}{150} \times \frac{6}{(30 + 60)}$

$\begin{array}{l} = \frac{3}{150} \times \frac{60}{90} = \frac{2}{150} A \\ V_{4} = i_{4} \times R_{4} = \frac{2}{150} \times 30 = \frac{2}{5} V = 0 .4 V \end{array}$

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