In Clark's method chemical added to hard water to remove its hardness is :

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$C a {(O H)}_{2}$

$C a O$

$C a C O_{3}$

$M g {(O H)}_{2}$

answer is C.

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Detailed Solution

Temporary hardness of water is removed in Clark's process by adding lime.

Ca(HCO₃)₂+Ca(OH)₂→2CaCO₃↓+2H₂O

Temporary hardness of water is due to the presence of bicarbonates of magnesium and calcium. They react with calcium hydroxide to form carbonates of magnesium and calcium. Thus, the temporary hardness of water is removed.

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