In [Co(H₂O)₆]²⁺, there are three unpaired electrons present. The $μ$ _calculated is 3.87 BM which is quite different from the $μ$ _experimental of 4.40 BM. This is because of

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increase in number of unpaired electrons

some contribution of the orbital motion of the electron to the magnetic moment

d-d transition

change in orbital spin of the electron

answer is B.

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Detailed Solution

[Co(H₂O)₆]²⁺ have three unpaired electron so its calculated value of magnetic moment is 3.87 BM but it has also some contribution form orbitals angular momentum and its value found is 4.40 BM.

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