In constant volume calorimeter, 3.5 g of a gas with molecular weight 28 was burnt in excess oxygen at 298.0 K. The temperature of the calorimeter was found to increase from 298 K to 398.45 K due to the combustion process. Given that the heat capacity of the calorimeter is 2.5 kJ K^-1 , the numerical value for the enthalpy of combustion of the gas in kJ mole^-1 is __

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answer is 9.

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Detailed Solution

Enthalpy of combustion of 3.5 g of the gas $= 2.5 \times 0.45 = 1.125 kJ$ Enthalpy of combustion per mole = 1.125/3.5/28 = 9

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