In Daniell cell oxidation of zinc and reduction of copper take place at

In Daniell cell, electrons are produced at the anode due to oxidation of Zn and at cathode electrons are absorbed due to reduction of copper (${\mathrm{Cu}}^{2+}$).

$\text{ i.e. (i) }\mathrm{Zn}⟶{\mathrm{Zn}}^{2+}+2{\mathrm{e}}^{-}\text{(at anode) }$

$\text{ (ii) }{\mathrm{Cu}}^{2+}+2{\mathrm{e}}^{-}⟶\mathrm{Cu}\text{ (at cathode) }$