In Deacon’s process $4 HCl + O_{2} \overset{X}{⟶} 2 {Cl}_{2} + 2 H_{2} O \cdot' X'$ may be

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$\frac{{C u C l}_{2}}{723 k}$

$\frac{{M n O}_{2}}{723 k}$

$\frac{H_{2} {SO}_{4}}{723 k}$

$\frac{P_{2} O_{5}}{723 k}$

answer is C.

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Detailed Solution

Deacon process is the preparation of chlorine gas using Hydrochloric acid gas with atmospheric oxygen (raw oxygen straight from photosynthesis) using a catalyst (cupric chloride).

4HCl+O₂→2H₂O+2Cl₂

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