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Q.

In diamond, carbon atom occupy fcc lattice points as well as altenate tetrahedral voids. If edge length of the unit cell is 356 pm, then diameter of carbon atom is:

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a

154.14 Pm

b

251.7 pm

c

77.07 Pm

d

89 Pm

answer is B.

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Detailed Solution

3a=4(2r)

2r = 1.732×3564= 77.07 pm

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