In double slit experiment fringes are obtained using light of wavelength 4800 Å. One slit is covered with a thin glass film of refractive index. 1.4 and another slit is covered by a film of same thickness but refractive index 1.7. By doing so the central fringe is shifted to fifth bright fringe in the original pattern. The thickness of glass film is

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8 × 10^-3 mm

4 × 10^-3 mm

6 × 10^-3 mm

2 × 10^-3 mm

answer is D.

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Detailed Solution

$\begin{array}{l} (μ_{1} - 1) t - (μ_{2} - 1) t = nλ; \Rightarrow t [μ_{1} - μ_{2}] = nλ \\ t = \frac{5 \times 4800 \times 10^{- 10}}{(1 .7 - 1 .4)} = \frac{5 \times 48 \times 10^{- 8}}{0 .3} \\ = 8 \times 10^{- 6} m = 8 \times 10^{3} mm \end{array}$

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