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Q.

In Dumas method, ‘ $x$ ’ grams of an organic compound containing nitrogen liberated 23.4cc of $N_{2}$ at STP. If the mass percentage of nitrogen in the compound is 46.8 then the value of ‘ $x$ ’ is

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a

$\frac{1}{12} gram$

b

$\frac{1}{16} gram$

c

$\frac{1}{8} gram$

d

$\frac{1}{4} gram$

answer is C.

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Detailed Solution

$\begin{aligned} % of N = \frac{V}{8 W} \\ 46.8 = \frac{23.4}{8 W} \\ W = \frac{1}{16} g \end{aligned}$

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