In each figure of column-I, a spherical uniform charge distribution is given in column-II, direction of electric field is represented by arrows. Match the direction of electric field due to charge distribution at given point in figures of column-I.
Column-I Column-II
A) A solid hemisphere, uniformly positive charged direction of resultant electric field at point P must be (point P lies on diameter AB as shown)
P)
B) A solid uniformly positive charged hemisphere with a hemispherical cavity and $C_{1}$ and $C_{2}$ are the centres of hemispheres, direction of resultant electric field at point $C_{2}$ can be
Q)
C) A solid uniformly positive charged hemisphere with a hemispherical cavity and $C_{1}$ and $C_{2}$ are the centres of hemispheres, $C_{1} P = C_{2} P = \frac{R}{4}$ where R is radius of hemisphere and radius of cavity is $\frac{R}{2}$ . Direction of resultant electric field at point P must be R)
D) A solid hemisphere, uniformly charged, direction of resultant electric field at centre C can be
S)
T)

Question

Infinity Learn · Accepted Answer

$A - R, B - R, C - R, D - S T$

Detailed Solution

	Column-I		Column-II
A)	A solid hemisphere, uniformly positive charged direction of resultant electric field at point P must be (point P lies on diameter AB as shown)	P)
B)	A solid uniformly positive charged hemisphere with a hemispherical cavity and $C_{1}$ and $C_{2}$ are the centres of hemispheres, direction of resultant electric field at point $C_{2}$ can be	Q)
C)	A solid uniformly positive charged hemisphere with a hemispherical cavity and $C_{1}$ and $C_{2}$ are the centres of hemispheres, $C_{1} P = C_{2} P = \frac{R}{4}$ where R is radius of hemisphere and radius of cavity is $\frac{R}{2}$ . Direction of resultant electric field at point P must be	R)
D)	A solid hemisphere, uniformly charged, direction of resultant electric field at centre C can be	S)
		T)