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Q.

In electrolysis of an aqueous solution of sodium sulphate, 2.4 L of oxygen at STP was liberated at anode. The volume of hydrogen at STP liberated at cathode would be 

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a

2.4 L

b

2.6 L

c

4.8 L

d

1.2 L

answer is D.

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Detailed Solution

Na2SO4→2Na++SO42−Anode: 2H2O→4e−+4H++O2           2.4 LCathode: 2H++2e−→H24H++4e−→2H2Total H2 gas leberated = 2×2.4=4.8 L

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