In electrolysis of dilute ${\mathrm{H}}_2{\mathrm{SO}}_4$ which is liberated at anode in presence of inert electrode ? 

When aqueous solution of sulphuric acid is electrolyzed , the following reactions takes place. 

$$\begin{gathered} \mathrm{Cathode} :\hspace{0.17em}2{\mathrm{H}}^{+\hspace{0.17em}}+\hspace{0.17em}2\hspace{0.17em}\mathrm{e}{ }^{-}\to {\mathrm{H}}_2 \\ \mathrm{Anode}:\hspace{0.17em}4{\mathrm{OH}}^{-}\to 2{\mathrm{H}}_2\mathrm{O} +\hspace{0.17em}\mathrm{O}{\hspace{0.17em}}_2+\hspace{0.17em}4{\mathrm{e}}^{-} \end{gathered}$$