In Escherichia coli the average no. of base pairs polymerized per second during DNA replication by the activity of DNA polymerase is

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$4.6 \times 10^{6}$

$3.3 \times 10^{9}$

$6.6 \times 10^{9}$

$2 \times 10^{3}$

answer is D.

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Detailed Solution

E. coli that has only 4.6 ×10⁶bp completes the process of DNA replication by the action of DNA polymerase within 18 minutes; that means the average rate of polymerisation has to be approximately 2000 bp per second.

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