In F₂ generation of Mendel’s dihybrid cross round and wrinkled seed shape segregated in the ratio of

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1 : 1 : 1 : 1

3 : 1

9 : 3 : 3 : 1

1 : 1

answer is A.

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Detailed Solution

Let's consider the alleles for seed shape:

Round seed shape (dominant): R
Wrinkled seed shape (recessive): r

In the F1 generation, when the two heterozygous parents (Rr x Rr) are crossed, the possible genotypes of the offspring are:

RR (Round seed shape) - 25%
Rr (Round seed shape) - 50%
rr (Wrinkled seed shape) - 25%

Now, when the F1 generation individuals are allowed to undergo random mating, the F2 generation will have various combinations of these genotypes. The F2 generation will segregate into the following phenotypic ratio:

9/16 will have Round seed shape (RR or Rr)
3/16 will have Round seed shape (Rr)
3/16 will have Round seed shape (Rr)
1/16 will have Wrinkled seed shape (rr)

So, the phenotypic ratio in the F2 generation of Mendel's dihybrid cross for seed shape will be 12: 4 or 3:1.

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