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In Fe-extraction, the roasting is adopted though the ore is not having any sulphide because

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Haematite is to be decomposed

All $F e O$ is to be converted into $F e_{2} O_{3}$

All $F e_{2} O_{3}$ is to be converted into $F e O$

Slag formation is encouraged

answer is B.

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Detailed Solution

To convert $F e O$ into $F e_{2} O_{3}$ otherwise $F e O$ can combine with $S i O_{2}$ present as gangue in the haematile ore.

$F e O + \underset{(g a n g u e)}{S i O_{2}} \to F e S i O_{3}$

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