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In fig., a block of weight 60 N is placed on a
rough surface. The coefficient of friction between the block and the surface is 0.5. What should be the weight W such that the block does not slip on the surface ?

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60 N

(60/√2)N

30 N

(30/√2)N

answer is C.

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Detailed Solution

$\begin{array}{l} F = μR = 0 \cdot 5 \times mg = 0 \cdot 5 \times 60 N = 30 N \\ Now F = T_{1} = T_{2} \cos 45^{\circ} or 30 = T_{2} \cos 45^{\circ} \\ and W = T_{2} \sin 45^{\circ} \\ ∴ W = 30 N \end{array}$

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