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In fig. shown the man of mass 50 kg is holding block of mass 10 kg. The reading of machine

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80 kg

90 kg

60 kg

70 kg

answer is B.

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Detailed Solution

R = mg

$= (50 + 10) 10$

${mg}^{1} = 60 \times 10 [∵ g^{1} = 10 {m/s}^{2}]$

$m = \frac{600}{10} = 60 kg$

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