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In Figure, coefficient of static friction $μ_{s}$ between block A of mass 2kgand the table is 0.2. Maximum mass of block B so that the two blocks do not move, is: (g = 10 m/s²)

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2.0 kg

0.2 kg

4.0 kg

0.4 kg

answer is D.

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Detailed Solution

According to question ,T = f
But $T = m_{B} g and f \leq {μm}_{A} g$
$\begin{array}{l} \Rightarrow m_{B} g \leq {μm}_{A} g \\ \Rightarrow {(m_{B})}_{max} = {μm}_{A} = 0 .2 (2) = 0 .4 kg \end{array}$

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