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In figure shown, a carriage P of mass 50 kg is slowly pulled up from A to B. The relevant coefficient of friction is 0.40. Then the work done is

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10 KJ

23 KJ

25 KJ

28 KJ

answer is B.

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Detailed Solution

$\begin{array}{l} Work done = mgh + μmgcosθ \times l \\ = 50 \times 10 \times (30 + 0 .4 \times \frac{4}{5} \times 50) Joule \\ = 23 KJ \end{array}$

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