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Q.

In figure, the ammeter (I) reads a current of 10 mA, while the voltmeter reads a potential difference of 3 V. The ammeters are identical, and the internal resistance of the battery is negligible (consider all ammeters and voltmeters as non-ideal). The resistance of ammeter is $m \times 10^{2} Ω .$ What is the value of m?

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Detailed Solution

$R_{A} = r e s i s \tan c e o f a m m e t e r$

$1 V - 0 V = (10 m A) R_{A} o r R_{A} = 100 Ω$

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