In figure the mass of the block $M = 1 kg$, $\mu = 0.5$ and $\sin \theta = \frac{3}{5}$. The acceleration of the block if $F = 10 N$:

$N = Mg-f\sin \theta ..........\left(i\right)$

and                      $f = \mu N ........\left(ii\right)$

Now           $\left(F=F\cos \theta \right)-f=Ma ..... \left(iii\right)$

After solving above equations, we get

                     $a = 12 m/s^2$