In finding H.C.F of two numbers by division method the quotients are 2, 2, 3 respectively and the last divisor is 18. Find the greater number.

H.C.F of 5 numbers by division method the Quotients

Last Quotient is 3 last division is 18

$\begin{array}{l}Dividend=Divisor\times Quotient+\mathrm{Re}mainder\\ =18\times 3=54\end{array}$

New remainder is 18, Now new divisor = 54, New Quotient is 2

So new dividend $=54\times 2+18$

$=126$

Second new divisor = 126 and new Quotient = 2,  remainder = 54

$\therefore newdividend=126\times 2+54$

       $=306$

So the Numbers are 126, 306