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Q.

In five complete rotations, the distance moved by screw on a linear scale is 0.5 cm. There are 100 divisions on circular scale. While measuring the thickness of a metal plate by the screw gauge, there are five divisions on the main scale and 35 divisions coincide with the reference line. Calculate the thickness of metal plate,

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a

5.35 cm

b

0.535 cm

c

0.6 cm

d

0.7 cm

answer is B.

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Detailed Solution

Least count = Pitch  Number of divisions on circular scale 

=0.55100=0.1100 cm=0.001 cm

Thickness = 5×0.1+35×0.001

=0.535 cm

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