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In front of a concave lens of focal length $20 cm,$ a $6 cm$ tall object is placed so as to obtain its image at $15 cm$ from the lens. Size of the image formed will be ____ $cm$ .

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Detailed Solution

In front of a concave lens of focal length

20 cm,

6 cm

tall object is placed so as to obtain its image at

15 cm

from the lens. Size of the image formed will be

1.5 cm

.
Given,
Focal length,

f

= - 20 cm

Image distance,

v =

15 cm

From lens formula,

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

here

f

is the focal length,

u

is the object distance and

v

is the image distance.

\frac{1}{- 15} - \frac{1}{u} = \frac{1}{- 20}

u = - 60

cm

h^{'} = \frac{v}{u} \times h

h'

is the height of the image and

h

is the height of the object.

\Rightarrow \frac{- 15}{- 60} \times 6 = 1.5 cm

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