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In gaseous triethyl amine the “–C–N–C” bond angle is degree.

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108^o

119^o

127^o

96^o

answer is A.

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Detailed Solution

Given data:
It is given to identify the degree in gaseous triethyl amine the “–C–N–C” bond angle.

Explanation:

Considering three bond pairs and one lone pair in triethylamine, nitrogen is $s p^{3}$ hybridised according to VSEPR theory, and the bond angle is 108^o.

Hence, the correct option is option (A) 108^o.

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