In Goldschmidt aluminothermic process, the thermite mixture contains:

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1 part ${Fe}_{2} O_{3}$ and 12 parts $Al$

3 parts ${Fe}_{2} O_{3}$ and 2 parts Al

3 parts ${Fe}_{2} O_{3}$ and 1 part $Al$

3 parts ${Al}_{2} O_{3}$ and 4 parts Al

answer is D.

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Detailed Solution

In Goldschmidt aluminothermic process, the thermite mixture contains 3 parts ${Fe}_{2} O_{3}$ and 1 part aluminum.

In this process $Al$ reduces ${Fe}_{2} O_{3}$ into $Fe$ with high temperature. Goldschmidt aluminothermic process is used to Thermite welding.

${Fe}_{2} O_{3} + 2 Al \to {Al}_{2} O_{3} + 2 Fe$

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