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In $H_{2} O_{2}$ The dihedral angle in gas phase and solid phase is respectively.

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${90.2}^{0}, {111.5}^{0}$

${94.8}^{0}, {101.9}^{0}$

${101.9}^{0}, {94.8}^{0}$

${111.5}^{0}, {90.2}^{0}$

answer is D.

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Detailed Solution

In solid phase dihedral angle is less than in gaseous phase.

Solid phase – ${90.2}^{0}$ , Gas phase - ${111.5}^{0}$

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