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In Haber process 30 liters of dihydrogen and 30 liters of dinitrogen were taken for reaction which
yielded only 50% of the expected product. What will be the composition of gaseous mixtureunder the aforesaid condition in the end.

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20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen

10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen

20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen

20 litres ammonia, 20 litres nitrogen, 15 litres hydrogen

answer is C.

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Detailed Solution

$N_{2} {+ 3H}_{2} ⇌ {2NH}_{3}$

$30 30 0$

$30 - x 30 - 3x 2x$

20 L should come on complete reaction

$∴$ 50% to of it is 2x = 10; x = $\frac{10}{2} = 5$

$N_{2} = 30 - 5 = 25 litre$

$H_{2} = 30 - 3 × 5 = 15 litre$

${NH}_{3} = 2 × 5 = 10 litre$

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