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In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded:

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$^{22} C_{10}$

$^{18} C_{3}$

$^{12} C_{4}$

$^{18} C_{4}$

answer is C.

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Detailed Solution

6 particular players are always to be included and 4 are always excluded, so total number of selection, now 4 players out of 12. Hence number of ways $=^{12} C_{4}$

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