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In how many ways a team of 11 players can be formed out of 25 players, if 6 out of them are always to be included and 5 are always to be excluded

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2020

2002

2008

8002

answer is B.

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Detailed Solution

C19= 1540, {Since books are same}. 44. (b) Since 5 are always to be excluded and 6 always to be included, therefore 5 players to be chosen from 14. Hence required number of ways are

$^{14} C_{5} = 2002$

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