In how many ways the number $10800$ can be resolved as a product of two factors?

Let $N=10800=2^4\times 3^3\times 5^2$

Here, $N$ is not a perfect square [$\because$ power of $3$ is odd] 

Hence, the number of ways $=\frac{1}{2}(4+1)(3+1)(2+1)=30$