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In hydrogen atom, electron makes transition from n=4 to n=1 level. Recoil momentum of the H atom will be

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$3.4 \times {10^{ - 24}}N{\text{ - sec}}$

$3.4 \times {10^{ - 27}}N{\text{ - sec}}$

$6.8 \times {10^{ - 27}}N{\text{ - sec}}$

$6.8 \times {10^{ - 24}}N{\text{ - sec}}$

answer is B.

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Detailed Solution

$Recoil{\text{ }}momentum{\text{ }} = {\text{ }}momentum{\text{ }}of{\text{ }}photon = \frac{h}{\lambda }$

$= hR\left( {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right) = \frac{{hR \times 15}}{{16}} = 6.8 \times {10^{ - 27}}N \times \sec$

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