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In Hydrogen atom, radial distance is maximum between

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n = 1 to n = 2

n = 2 to n = 3

n = 3 to n = 4

n = 4 to n = 5

answer is D.

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Detailed Solution

$r_{n} = \frac{n^{2}}{Z} r_{o}; Z = 1 for H - atom, r_{0}, 4 r_{0}, 9 r_{0}, 16 r_{0}, 25 r_{0} - - radius of first five orbits .$

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