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Q.

In hydrogen atom the Debroglie wave length of an electron in the second Bohr orbit is [Given that Bohr radius $\propto_{0} = 52.9 P m$

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a

$211.6 π P m$

b

$52.9 π P m$

c

$211.6 P m$

d

$105.8 P m$

answer is C.

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Detailed Solution

$r_{n} = n^{2} \times r_{1}$

$r_{2} = 2^{2} \times 52.9 p m$

$n λ = 2 π r_{n}$

$λ = \frac{2 π}{n} r_{n}$

$λ = \frac{2 π}{2} \times 52.9 \times 2^{2}$

$λ = 211.6 π p m$

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